In the given reaction: C_6H_5-CH=O xrightarro | vedclass

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(C) The reaction of benzaldehyde $(C_6H_5-CHO)$ with hydroxylamine $(NH_2OH)$ in an acidic medium produces benzaldoxime $(C_6H_5-CH=N-OH)$.Since the c

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Mixture of syn and anti oxime

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(C) The reaction of benzaldehyde $(C_6H_5-CHO)$ with hydroxylamine $(NH_2OH)$ in an acidic medium produces benzaldoxime $(C_6H_5-CH=N-OH)$.Since the carbon atom in the $C=N$ bond is attached to two different groups ($H$ and $C_6H_5$),the resulting oxime exhibits geometrical isomerism.Therefore,the product $[X]$ is a mixture of syn and anti oximes.

In the given reaction: $C_6H_5-CH=O \xrightarrow{NH_2OH/H^{+}} [X]$. $[X]$ will be:

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